Error with formula

daniels012

daniels012

Well-known Member
Joined
Jan 13, 2005
Messages
5,219
I am getting an #NA error with this formula?
It has worked forever, why all of the sudden would it not be working?
=IF(B20<>"",INDEX(B19:B51,MATCH(TRUE,INDEX(NOT(ISNUMBER(B19:B51)),),FALSE)-1),B19[FONT=Inconsolata, monospace, arial, sans, sans-serif])
[/FONT][FONT=Inconsolata, monospace, arial, sans, sans-serif]
[/FONT]Thanks
 

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As Ron says, your formula fails with all numeric as the below

TRUE,INDEX(NOT(ISNUMBER(B19:B51) evaluates to

TRUE,INDEX({FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE;FALSE}
 
Upvote 0
The problem must be in the referenced range. Check each referenced cell for anomalies. Let us know what you find.
 
Upvote 0
How about possible help in changing this formula.
I just posted another post to replace this formula.
Here is my goal.
I know the first cell is B19
I need to get the last value in column "B" and I know there will be values contiguous up to a blank or text.
Is there a much simpler solution?

Thank you both for your quick responses
michael D
 
Upvote 0
use something like

SUM(B19:INDEX(B:B,COUNTA(B:B)+18)) to get your B range
 
Upvote 0
If you want the last numeric value in B39:B51, try this regular formula:
=LOOKUP(10^10,B19:B51)

Does that help?
 
Upvote 0
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